Answer:
1: 30
2: 20
3: 6
Step-by-step explanation:
1: .60 x 50 = 30
2: .50 x 40 = 20
3. .12 x 50 = 6
Idk why your two answers for 3 are 20 and 30 but neither of those are the answer
Jelly beans - $0.98 per pound
chocolate drops - $0.67 per pounds
Terri's bag = 2.1 pounds and $1.56
p = represents the pounds jelly beans.
c = represents the pounds in chocolate drops
p + c = 2.1
0.98p + 0.67c = 1.56
c = 2.1 - p ; number of pounds of chocolate drops
0.98p + 0.67(2.1 - p) = 1.56
0.98p + 1.41 - 0.67p = 1.56
0.98p - 0.67p = 1.56 - 1.41
0.31p = 0.15
p = 0.15/0.31
p = 0.48 pounds of jelly beans
c = 2.1 - 0.48
c = 1.62 pounds of chocolate drops.
Y = mx + b is the standard form for slope intercept
The percentage of the runners who have times less than 14.4 sec is 0.15%
The times of all 15-year old who run a certain race are approximately normally distributed with a given mean of 18 sec and a standard deviation of 1.2 sec.
We know that,
where,
X = raw score = 14.4
μ = mean = 18
σ = standard deviation = 1.2
Putting the values,
Finding the probability from the z score table, we get
P(z < -3) = 0.00135 = 0.135%
Disclaimer: The question is incomplete. Please read below to find the missing content.
Question: The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean of 026-1 = 18 seconds and a standard deviation of 026-2. = 1.2 sec. What percentage of the runners have times less than 14.4 seconds?
0.15%
0.15%
0.30%
0.60%
2.50%
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I know it!!! just wait so i can finsih expaimning it
im smart
