Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
Well there are many different ways to find 8x5=40 to 8x6=__
You could add 8 to 40 and get 48.
or you could draw pictures to represent the 48.
8x6=48
Aw you put the numbers in so a b c then you solve
It’s a big problem it’s deserve 20 points you can’t play people make it fair
1. irrational: √48 = 6.92820323028
2. rational: √9 = 3
3. irrational: √39 = 6.2449979984
4. rational: √289 = 14
