Answer:
y = 5 e^r * t
Let y be the population in billions and t the value of elapsed years
7 = 5 e^r * t is the equation being used where t = 15
7/5 = e^r * t
ln 7/5 = r * t taking ln of both sides
r = .336 / 15 = .0224
y = 5 e^(.0224 t) is then our equation
Check - suppose you want y at 2020
y = 5 e^(.0224 * 20) would be the equation
y = 5 e^.449 = 7.83 billion - seems to be a reasonable answer
Answer:
See answer below
Step-by-step explanation:
The possible zeroes are p/q where p is factors of the constant and q is factors of the coefficient of the largest degree.
This means possible zeroes are ±15/4, ±5/4, ±3/4, ±1/4, ±15/2, ±5/2, ±3/2, ±1/2, ±15, ±5, ±3, ±1.
The greatest common factor of 135 225 and 270 is 135/225 = 3/5
hope you found this helpful ;)
