Quadrilateral BCDE is inscribed in circle A. EBC and BCD measure

A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

8 0

3 years ago

5x−4≥12 OR 12x+5≤−4 please answer asap and right and explain like im 5 how to solve OR problems ill give brainliest and a lot of

weeeeeb [17]

Answer: x>_3.2 OR x<_ -0.75

Step-by-step explanation: first break down your compound inequality. 5x-4>_12

You first cancel out your constants by adding 4 to both sides. Now you’re left with 5x>_16 then to cancel five you have to divide on both sides by five which equals to 3.2. Then, x>_ 3.2.

Next you do your second part, 12x+5<_-4

So first cancel out the constant of 5 by subtracting 5 on both sides, making the equation 12x<_-9. Now, you divide by 12 on both sides, making it -9/12. Which effectively is -0.75. Therefor, the answer being x<_ -0.75. Add the two together x>_3.2 OR x<_0.75

4 0

2 years ago

Graph this inequality on the number line.<br><br> x ≤ 2.6

pantera1 [17]

x ≤ 2.6 would look like this on the number line, the 2.6 part would be shaded in as well and not left open since x is less than OR EQUAL to 2.6

7 0

2 years ago

The table below represents a linear function.

ohaa [14]

(-1,5)(1,9)
slope = (9 - 5) / (1 - (-1) = 4 / (1 + 1) = 4/2 = 2

y = mx + b
slope(m) = 2
use any of ur points in the table....(1,9)...x = 1 and y = 9
now we sub ad find b, the y int
9 = 2(1) + b
9 = 2 + b
9 - 2 = b
7 = b

so ur equation of the table is : y = 2x + 7.....where the slope = 2 and the y intercept = 7

so, the equation with the greater slope and the greater y int is :
y = 3x + 7.5....this has a slope of 3 and a y int of 7.5

8 0

3 years ago

A large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and

scoundrel [369]

Answer:

-6.134 to +6.134

Step-by-step explanation:

given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution

X is Normal with mean =6.1 and std dev = 1 unit

We are to determine the range of values containing 70% of the population of x

We know that normal distribution curve is bell shaped symmetrical about the mean.

So to find 70% range we can use 35% on either side of the mean

Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034

Hence corresponding x value is

$x=6.1+1.034*1\\x=6.134$

i.e. 70% values lie between

-6.134 to +6.134

3 0

3 years ago

Read 2 more answers