1. Observe that the f(t) is change by 4 per time t => there's a acceleration of 4 => f''(t) = 4; Take the derivative of it we can get a velocity function. f'(t) = 4t + c. Since the velocity from 100 to 80 is -20 (average), this means at t = 0, f'(0) = -22 => f'(t) = 4t - 22; Take the derivative again to get the position function: f(t) = 2t^2 - 22t + d, here d = 100 should be trivial. So, the function that models the relationship is f(t) = 2t^2 - 22t + 100.
2. By the compound interest formula:
A = P (1 + r/n)^(nt) , since it's yearly, so n = 1;
results A(t) = 100 (1+0.12)^t.
3. The average rate of change is basically finding the slope, m = y1 - y2 / x1 - x2.
Answer:
323 mod 5 = 3
−323 mod 5 = -3
327 mod 3 = 0
(64 * (-67) + 201) mod 7 = 6
(38^12) mod 6 = 4
(38^12) mod 3 = 1
Step-by-step explanation:
The modulo operation looks for remainders from the quotients. In order to find them, divide the whole number by the mod number. Then take just the decimal after the whole answer and multiply it by the mod number.
<u>323 mod 5</u>
323/5 = 64.6
.6 * 5 = 3
<u>−323 mod 5</u>
323/5 = -64.6
-.6 * 5 = -3
<u>327 mod 3</u>
327/5 = 109
0 * 3 = 0
<u>(64 * (-67) + 201) mod 7</u>
64 * -67 = -4288 + 201 = 4087
4087/7 = 583.85714
.85714 * 7 = 6
<u>(38^12) mod 6</u>
38^12 = 9.07x10^18
9.07x10^18/6 = 1510956318082499242.6666667
.666667 * 6 = 4
<u>(38^12) mod 3</u>
38^12 = 9.07x10^18
9.07x10^18/3 = 3021912636164998485.333333
.3333333 * 3 = 1
Answer:
9 two year olds, 18 three year olds, 18 four year olds
Step-by-step explanation:
Let's say x is the number of 2 year olds. There are double the number of three year olds (2x) . Four year olds is the same as 3 year olds (2x).
x + 2x +2x = 45
5x=45
x= 9
Double is 18 for 3 and four year olds.
Answer:
11.25
Step-by-step explanation:
Theres your answer