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STALIN [3.7K]
3 years ago
9

The equation of the line perpendicular to 5x + 2y = 20 and containing the point (5, 2) is:

Mathematics
1 answer:
Rainbow [258]3 years ago
5 0
Two perpendicular lines have slopes that are negative reciprocals of each other, that is, if one slope is a/b, the other is -b/a
the first line 5x+2y=20, 2y=-5x +20, y=-5/2 x+10, the slope is -5/2, so the perpendicular line's slope is 2/5
the equation in point-slope form is (y-2)=(2/5)(x-5)
in slope-intercept form: y=(2/5)x
in standard form: 2x-5y=0
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Is the point (1,3) a solution to the linear equation 5x-9y=32? explain
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There are many ways to check if the point (1,3) is a solution to the linear equation 5x-9y=32.

Let us check it by expressing y in terms of x.

The given expression is 5x-9y=32. If we add -5x to both sides we will get:

-9y=-5x+32

Multiplying both sides by -1 we will get:

9y=5x-32

In order to isolate y, we will divide both sides by 9 to get:

y=\frac{5}{9}x-\frac{32}{9}

Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.

y=\frac{5}{9}\times 1-\frac{32}{9}=\frac{5-32}{9}

\therefore y=\frac{-27}{9}=-3

Thus, we see that when x=1, y=-3 and that y\neq 3 and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.

For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.





3 0
3 years ago
Read 2 more answers
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