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3 years ago

How do I find the Greatest common factor??

2 answers:

7 0

factors of a number are those numbers that can divide the number exactly without leaving a reminder.

using 6 and 12 as an example

factors of 12 {1,2,3,4,6,12}

factors of 6 { 1,2,3,6}

then the common factor from both 6 and 12 are { 1,2,3,4,6}

and from this , the greatest common factor is 6.

Agata [3.3K]3 years ago

4 0

Answer:

1. List the prime factors of each number

2. Multiply those factors both factors have in common. If there are no common prime factors the GCF is 1.

Step-by-step explanation:

Use the factor tree method

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A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 1:4.

schepotkina [342]

Let point C has coordinates $(x_C,y_C).$ Consider vectors

$\overrightarrow{AB}=(x_B-x_A,y_B-y_A)=(8-9,6-9)=(-1,-3),\\ \\\overrightarrow{BC}=(x_C-x_B,y_C-y_B)=(x_C-8,y_C-6).$

Since the ratio AB to BC is 1:4, you have that

$\dfrac{-1}{x_C-8}=\dfrac{1}{4}\quad \text{and}\quad \dfrac{-3}{y_C-6}=\dfrac{1}{4}.$

Find $x_C$ and $y_C:$

$x_C-8=-4,\\ \\x_C=-4+8=4,\\ \\y_C-6=-3\cdot 4=-12,\\ \\y_C=-12+6=-6.$

Answer: C(4,-6)

7 0

2 years ago

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The sum of two consecutive odd integers is greater than 36 (solve with an inequality and show work please)

mixas84 [53]

O+o+2>36
2o>34
o>17
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4 0

2 years ago

Sidney is making greeting cards, which she will sell by the box at an arts fair. She paid $32 for a booth at the fair, and the m

borishaifa [10]

So think of it like this she starts off $32 negative and subtract 3 from each box of cards she makes . So each box of cards she will make $8 that being said

32/8 =4 (it will take 4 box of cards to pay off her booth expense).

Sales would be 11x 4 =44

Expenditures would be 3x4 =32 (the amount used to make cards ) +32(the amount paid for the booth)

Which in total would be $64

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3 years ago

Suppose the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months. W

rusak2 [61]

Answer:

Probability that the calculator works properly for 74 months or more is 0.04 or 4%.

Step-by-step explanation:

We are given that the life span of a calculator has a normal distribution with a mean of 60 months and a standard deviation of 8 months.

Firstly, Let X = life span of a calculator

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 60 months

$\sigma$ = standard deviation = 8 months

Probability that the calculator works properly for 74 months or more is given by = P(X $\geq$ 74 months)

P(X $\geq$ 74) = P( $\frac{ X - \mu}{\sigma}$ $\geq$ $\frac{74-60}{8}$ ) = P(Z $\geq$ 1.75) = 1 - P(Z < 1.75)

= 1 - 0.95994 = 0.04

Therefore, probability that the calculator works properly for 74 months or more is 0.04 or 4%.

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2 years ago

5x + 7x + 2x + 8 -2 please helppp

Murljashka [212]

Answer:

= 14X + 6

Step-by-step explanation:

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2 years ago

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