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3 years ago

Ratio and Proportion can be used to convert weights between different systems of measurement. True False

Mathematics

2 answers:

sergeinik [125]3 years ago

7 0

The answer you are looking for is true

Dahasolnce [82]3 years ago

3 0

Answer:

The answer is true.

Step-by-step explanation:

Ratio and Proportion can be used to convert weights between different systems of measurement. This is true.

When we are given any problem with different measurements, then we should first convert the problem in such a unit that all units are the same.

We can define ratio as a comparison between two numbers.

Whereas the proportion is a comparison between two ratios.

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X is ........... variable | Maths Questions

makvit [3.9K]

Answer:

B. Independent

Step-by-step explanation:

Hope this helps

8 0

2 years ago

Read 2 more answers

1. What is greater? 6 pounds and 11 ounces OR 117 ounces? 2. 3/4 tons = how many pounds? (Answer the ones u know!) pls help due

lesya [120]

Answer:

1. Equal. 2. 1500

Step-by-step explanation:

6 x 16 = 96 + 11= 117

3/4 x 2000 = 1500

4 0

2 years ago

Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

3 years ago

Please help immediately

Burka [1]

Answer: $f'(1)=\dfrac{4}{2y+1}$

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given: 0 = 2x² - xy - y²

Derivative: 0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

y'(2y + 1) = 4x

$y'=\dfrac{4x}{2y+1}$

$\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}$

8 0

2 years ago

Hey guys i need some heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp- 15 points

masya89 [10]

Answer:

Step-by-step explanation:

3x + 2 + 58 = 90

3x + 60 = 90

3x = 30

x = 10

it's adjacent

8 0

2 years ago