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Arte-miy333 [17]
3 years ago
7

Can anybody help me with this problem 324 divided by 2,456?

Mathematics
1 answer:
UNO [17]3 years ago
3 0

Answer:

0.13192182

Step-by-step explanation:

324/2456

To solve, divide.

324/2456

This equals:

0.13192182

Hope this helps!

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The ratio of the measures of the sides of a triangle is 8: 15: 17, and its perimeter is 480 in.. Find the measure of the shortes
lubasha [3.4K]

Answer:

96

Step-by-step explanation:

The ratio of the measure of sides of a triangle are 8:15:17

The perimeter is 480

8x + 15x + 17x= 480

40x= 480

x = 480/40

x = 12

Therefore the measure of the shortest side of the triangle can be calculated as follows

8x

8×12

= 96

6 0
2 years ago
Arlo has 6 pairs of slacks and 4 dress shirts How many ways can Arlo choose one pair of slacks and one dress shirt? 2 6 10 24
Rashid [163]

For every pair of slacks Arlo can choose 4 dresses so the number of ways is

6 * 4 = 24 answer

5 0
2 years ago
Read 2 more answers
If the perimeter of this quadrilateral is 79 inches, what is the measure of the missing side length in inches?
Ilia_Sergeevich [38]

Answer:

79 = 13+15+24+ missing side. 79 = 52 + missing side

4 0
2 years ago
Read 2 more answers
What is the missing term in the factorization?
jasenka [17]
  • <em>Answer:</em>

<em>the missing term is 5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>12x² - 75 = </em>

<em>= 3(4x² - 25)</em>

<em><u>use formula</u></em><em> a² - b² = (a - b)(a + b)</em>

<em>= 3(2x - 5)(2x + 5)</em>

<em>= 3(2x + 5)(2x - 5) </em>

<em>the missing term is 5</em>

<em>Good luck !</em>

4 0
3 years ago
{ TOPIC -- TRIGONOMETRIC IDENTITIES }
UkoKoshka [18]
LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)

cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ))    [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ))    [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
8 0
2 years ago
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