Bria drank an 8-ounce glass of water from a 32-ounce container of water. How many more 8 ounce glasses were left?

Mathematics

1 answer:

marusya05 [52]2 years ago

4 0

There were 3 8-ounce glasses left, because 32 ounces - 8 ounces = 24 ounces, and 24/8 = 3. Hope this helped.

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jack has $7.55 of change in his pocket. if he has 4 more dimes than than nickels, and twice as many quarters as nickels, how man

dolphi86 [110]

Answer:

11 nickels, 15 dimes, 22 quarters

Step-by-step explanation:

number of nickels = x

number of dimes = x+4

number of quarters = 2x

- - - - - -

total of nickels = 5x cents

total of dimes = 10x + 40 cents

total of quarters = 50x cents

- - - - - -

755 = 5x + 10x + 40 + 50x

755 = 65x + 40

715 = 65x

x = 11

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8 0

2 years ago

Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq

Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

$\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9$

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

$125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9$