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Hoochie [10]
3 years ago
12

Help looks like i forgot to read a ruler

Mathematics
2 answers:
Sonja [21]3 years ago
8 0

Answer:

The answer might be A

Step-by-step explanation:

hope this helps

alexandr402 [8]3 years ago
3 0

Answer:

the answer is A

Step-by-step explanation:

because when looking at the ruler there is a 5 so the 5 is the whole number and when you move 5 spaces it is the numarotar and the 8 is the denomnator. hope it helpd

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Determine if the three numbers form a
IgorLugansk [536]

Answer:

A acute

Step-by-step explanation:

cause an acute it between 0-90 degrees

7 0
3 years ago
Algebraically determine the values of h and k to correctly complete the identity stated below 3x^3-6x^2+4x-2=(x-2)(3x^2+hx+4)+k
Marrrta [24]
We want to find h and k so that
3x³ - 6x² + 4x - 2 ≡ (x-2)(3x² + hx + 4) + k

Expand the right side.
(x-2)(3x² + hx + 4) + k
= 3x³ + hx² + 4x - 6x² - 2hx - 8 + k
= 3x³ + (h-6)x² + (4 - 2h)x + k - 8

Match coefficients of x²:
h - 6 = -6
h = 0

Match coefficients of x:
4 - 2h = 4    (Correct because h=0)

Match constants.
k - 8 = -2
k = 6

Answer:  h=0, k=6

4 0
3 years ago
I need help solving this. I am completely lost. It would be great if you would help me
AysviL [449]
Hope it helps!!!!!! :):):)

6 0
4 years ago
What equation defines a line through points (-2, 7) and (6, -9)
Tanya [424]

7 =  - 2k + b \\  - 9 = 6k + b \\  \\ 7 =  - 2k + b \\  9 =  - 6k  -  b \\  \\16 =  - 8k \\ k =  - 2

Now we can find b

7 =  - 2 \times ( - 2) + b \\ 7 = 4 + b \\ b = 3

Answer:

y =  - 2x + 3

4 0
3 years ago
Hown below are the top 15 market research firms in the United States in 2014 according to the AMA Gold Top 50 Report. Compute th
Maru [420]

Solution :

Number      Values (X)       $\sum (X_i - \bar X)^2$

    1               121.5            193494.4144

   2               138.9            178489.3504

   3                155.7    164576.2624

   4           172            151616.7844    

   5               172.9            150916.7104

  6              196.5             133137.4144

   7              202.3            128938.4464

  8              202.7            128651.3424

  9              334.5            51474.5344

  10               504            3292.4644

   11              563.7              5.3824

   12       574.1              161.7984

   13                935           139591.9044

  14              952.6        153053.0884

   15     3194.3           6932267.726

Total             8420.7         8509667.624

Mean $\bar X = \sum \frac{X_i}{n}$

              $=\frac{8420.7}{15}$

              = 561.38

Median :

$Q_2 = \left(\frac{1}{2}n+\frac{1}{2}\right)^{th}$value

     $ = \left(\frac{1}{2}\times 15+\frac{1}{2}\right)^{th}$value

    = 202.7

Percentile = $\left(\frac{P}{100} \times n + \frac{1}{2}\right)^{th}$  value

                 = $\left(\frac{50}{100} \times 15 + \frac{1}{2}\right)^{th}$ value

                 = 202.7

Percentile = $\left(\frac{P}{100} \times n + \frac{1}{2}\right)^{th}$  value

                 = $\left(\frac{40}{100} \times 15 + \frac{1}{2}\right)^{th}$ value

                 = 198.82

Percentile = $\left(\frac{P}{100} \times n + \frac{1}{2}\right)^{th}$  value

                 = $\left(\frac{90}{100} \times 15 + \frac{1}{2}\right)^{th}$ value

                 = 1849.28

$Q_1 = \left(\frac{1}{4}n+\frac{1}{4}\right)^{th}$value

     $ = \left(\frac{1}{4}\times 15+\frac{1}{4}\right)^{th}$value

    = 172

$Q_3 = \left(\frac{3}{4}n+\frac{3}{4}\right)^{th}$value

     $ = \left(\frac{3}{4}\times 15+\frac{3}{4}\right)^{th}$value

    = 574.1

Therefore, the range = highest value - lowest value

                                  = 3194.3 - 121.5

                                  = 3072.8

Now the interquartile range = $Q_3-Q_1$

                                              = 574.1 - 172

                                             = 402.1

8 0
3 years ago
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