What are the benefits of community policing? Choose all answers that are correct.

Mathematics

2 answers:

Ivenika [448]2 years ago

8 0

Answer:

I envisage that furthermore the answer is (A),(C) and (D)

Step-by-step explanation:

please mark me brainliest

stellarik [79]2 years ago

3 0

It would seem that the third answer would be right but I am only 60% sure if you do not know the answer for sure, choose C but if you would rather get the 100% answer just wait

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Raven is considering taking out a 30-year loan with monthly payments of

Anna007 [38]

Answer:

If Raven's monthly payment were $125, the amount of the loan that she is considering taking out would be less than $43,205.56.

Step-by-step explanation:

If you think about it this way it may be more simple. If the APR stays constant then a greater payment will result in a greater loan. The opposite is also true meaning a lesser payment will result in a lesser loan. If the amount Raven pays is greater than $145 then the loan will be greater than $43,205.56. If the amount she pays is less than $145 then the loan will be less than $43,205.56. Of the options, only one of these situations will be present. In my case, the correct option was a payment of $125 will result in a lesser loan than $43,205.56.

6 0

3 years ago

Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).

KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

$2x^2-3x-6=0$

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

$2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}$

We have to find the value of (a+2)(b+2).

Putting the values:

$(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4$