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Anna007 [38]
3 years ago
5

Is 1 yard greater than 1 meter

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
No, 1 yard is .9144 meters 
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Answer:

Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$

Step-by-step explanation:

8 0
3 years ago
Help it’s the mid chapter check point
marusya05 [52]

Answer:

77

Step-by-step explanation:

the opposite of a negative is a positive so -77 is just 77

8 0
3 years ago
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