4800 divide by 3=1600 (2 cars 1 truck)

4600-1600-3000 (6 cars)

3000 divide by 3 = 1000(2cars)

1000 times 2=2000(4 cars )

4800-2000-2800 (2 cars 3 trucks)

$2,800 is your answer

8 0

2 years ago

With full explanation from the internet like before 3x2-6x+5=0

Elodia [21]

Answer:

$\sf x=1+i\sqrt{\dfrac{2}{3}} \ \quad and \quad \:x=1-i\sqrt{\dfrac{2}{3}}$

Explanation:

Given Expression:

3x² - 6x + 5 = 0

Use the Quadratic Formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ \ ax^2 + bx + c = 0$

insert coefficients

$\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}$

$\Longrightarrow \sf x =1 \pm i\dfrac{\sqrt{6} }{3}$

$\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}}, \quad 1-i\sqrt{\dfrac{2}{3}}$

6 0

2 years ago

Read 2 more answers

Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th

Ilya [14]

Answer:

13 1/3 and 6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' = 40x - 3x^2 = 0 for maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and 6 2/3.

3 0

3 years ago

Yo, reasking bc wrong grade level, how do you find the slope as a right triangle?​

Yo, reasking bc wrong grade level, how do you find the slope as a right triangle?