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Elis [28]
3 years ago
10

Yo, reasking bc wrong grade level, how do you find the slope as a right triangle?​

Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0
Count from top and then go right or left
ehidna [41]3 years ago
4 0
Count down from the top one then count to the right or left ly
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Suhas puts 12 crayons in a box. Two of the crayons are orange. Suhas selects one crayon from the box without
il63 [147K]

Answer:

The probability that it isn't orange is 5/6

Step-by-step explanation:

There are twelve crayons and two are orange so there is ten that aren't orange. Probability being 10/12. We can now simplify to 5/6. There you go easy as.

Many regards, Abdelmumen Nakoa.

6 0
3 years ago
What is 1 1/2 plus 2/3?
belka [17]
1 3/6 + 4/6 = 1 7/6 = 2 1/6
3 0
3 years ago
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What the next number...2 7 8 3 12 9
ANEK [815]

-(17/30)n^5+(113/12)n^4-(173/3)n^3+ (1915/12) n^2- ( 5813/30)n +85

there fore term number 7 is .... -146/1=-146

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3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
Find the area of the shape shown below.<br> PL
amid [387]

Answer:

where is the shape of your question

5 0
4 years ago
Read 2 more answers
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