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ioda
3 years ago
12

X-5y=2 and 9x+8=15 solve by substitution

Mathematics
1 answer:
lozanna [386]3 years ago
7 0
x-5y=2
Hence x=2+5y   (Equation I)
9x+8=15             (Equation II)
Substituting Equation I in Equation II
9(2+5y)+8=15
18+45y+8=15
26+45y=15
45y=-11
Hence y= - \frac{11}{45}

Substituting this in Equation in I to get X

x-5(- \frac{11}{45} )=2
x+ \frac{11}{9}=2
x= 2- \frac{11}{9}
x= \frac{17}{9}
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R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)

B(4,2) Original Point

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C(4, -5) Original Point

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D(-1 , -5) Original Point

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Note: CCW means Counter Clockwise

The graph on the left is the same one you have been given.

The graph on the right is the same figure after all the transformations

7 0
3 years ago
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Step-by-step explanation:

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Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?
garri49 [273]

<u>Given</u>:

Given that the radius of the circle is 2 inches.

We need to determine the area of the remaining square.

<u>Area of a square:</u>

Given that each circle has a radius of 2 inches.

Then, the diameter of each circle is 4 inches.

Hence, the side length of the square is 2 × 4 = 8 inches.

The area of the square is given by

A=s^2

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A=64 \ in^2

Thus, the area of the square is 64 square inches.

<u>Area of the four circles:</u>

The area of one circle is given by

A=\pi r^2

Substituting r = 2, we have;

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Thus, the area of one circle is 4π in²

The area of 4 circles is 4 × 4π =16π in²

Hence, the area of the 4 circles is 16π in²

<u>Area of the remaining square:</u>

The area of the remaining square is given by

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Substituting the values, we get;

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Thus, the area of the remaining square is (64 - 16π) in²

Hence, Option c is the correct answer.

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