Question

X-5y=2 and 9x+8=15 solve by substitution

Answer 1

$x-5y=2$
Hence $x=2+5y$   (Equation I)
$9x+8=15$             (Equation II)
Substituting Equation I in Equation II
$9(2+5y)+8=15$
$18+45y+8=15$
$26+45y=15$
$45y=-11$
Hence $y= - \frac{11}{45}$

Substituting this in Equation in I to get X

$x-5(- \frac{11}{45} )=2$
$x+ \frac{11}{9}=2$
$x= 2- \frac{11}{9}$
$x= \frac{17}{9}$