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3 years ago

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X-5y=2 and 9x+8=15 solve by substitution

1 answer:

lozanna [386]3 years ago

7 0

$x-5y=2$
Hence $x=2+5y$ (Equation I)
$9x+8=15$ (Equation II)
Substituting Equation I in Equation II
$9(2+5y)+8=15$
$18+45y+8=15$
$26+45y=15$
$45y=-11$
Hence $y= - \frac{11}{45}$

Substituting this in Equation in I to get X

$x-5(- \frac{11}{45} )=2$
$x+ \frac{11}{9}=2$
$x= 2- \frac{11}{9}$
$x= \frac{17}{9}$

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