All categories

3 years ago

Not sure if it is hyperbola or hyperbole.

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

it is hyberbola

hope it helps you!

Juliette [100K]3 years ago

7 0

Answer:

obviously it's always gonna be hyperbola lol

You might be interested in

A bag holds 13 marbles. 6 are blue, 2 are green, and 5 are red. you select a marble from the bag. what is the probability that t

navik [9.2K]

Answer:

$\boxed {\boxed {\sf B. \ \frac{8}{13} }}$

Step-by-step explanation:

Probability is found by dividing the number of favorable outcomes by the total number of outcomes.

$P= \frac{favorable \ outcomes}{total \ outcomes}$

For this problem, the favorable outcome is selecting a blue or green marble. There are 8 outcomes for this because there are 6 outcomes for blue and 2 fr green.

The total outcomes are all the marbles. Each marble could be an outcome, so there are 13 outcomes (1 for each marble).

$P(blue \ or \ green) = \frac{8}{13}$

This fraction cannot be reduced, so the probability of selecting a blue or green marble is <u>8/13.</u>

7 0

3 years ago

6p-10c-8 when p=6 and c=8

ELEN [110]

The answer is 36 in simplist form

5 0

3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

Write using exponents. (–4)(–4) 2. simplify. show your work.

Dmitriy789 [7]

32 is the answer and you write it out by copying what's in the calculator

6 0

3 years ago

What is the measure of tje fourth angle of the quadrilateral

grin007 [14]

37 would be the answer.....

5 0

3 years ago