Make each adult x and each kid 5x
and
set equal to 14.
so it would be
3.5x=14.
14/3.5 = 4
so
x = 4.
adult tickets are 4$ while kids are 2$
Step-by-step explanation:
8.3 = 8+ 0.3
= 8 + 3/10
= 8 3/10
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
m∠TUV = 105
Step-by-step explanation:
From the question given above, the following data were obtained:
m∠TUN = 1 + 38x
m∠NUV = 66°
m∠TUV = 105x
m∠TUV =?
Next, we shall determine the value of x. This can be obtained as illustrated below:
m∠TUV = m∠TUN + m∠NUV
105x = (1 + 38x) + 66
105x = 1 + 38x + 66
Collect like terms
105x – 38x = 1 + 66
67x = 67
Divide both side by 67
x = 67 / 67
x = 1
Finally, we shall determine the value of m∠TUV. This can be obtained as shown below:
m∠TUV = 105x
x = 1
m∠TUV = 105(1)
m∠TUV = 105
