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Fittoniya [83]
3 years ago
14

What is the approximate value of x in the equation below. log 3/4 25 =3x-1

Mathematics
2 answers:
inessss [21]3 years ago
8 0

Solve for x by simplifying both sides od the equation, then isolating the variable.

x=79/12

n200080 [17]3 years ago
4 0

Answer:

Given the equation: \log_{\frac{3}{4}} 25 = 3x-1

Solve for x;

Use logarithmic rules:

\log_b a = \frac{\log a}{\log b}

Then;

\frac{\log 25}{\log \frac{3}{4}} =3x-1

Using values of:

\log 25 = 1.39794001

\log \frac{3}{4} = -0.124938737

Substitute these values we have;

-\frac{1.39794001}{0.124938737} = 3x-1

Simplify:

-11.1890039 =3x-1

Add 1 to both sides we get;

-10.1890039 = 3x

Divide both sides by 3 we get;

x = - 3.39633463

Therefore, the approximate  value of x in the equation  \log_{\frac{3}{4}} 25 = 3x-1 is -3.396


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Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
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<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

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=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

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Length of side adjacent to θ = x

Hypotenuse = 12

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=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

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Answer:

x = 0

Step-by-step explanation:

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