Answer:
The products of AB and BA is given by
AB=![\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D21%26-6%5C%5C%209%263%5Cend%7Barray%7D%5Cright%5D)
BA=![\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-1%5C%5C-18%2615%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrices A=![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D)
and
B=![\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-1%5C%5C-3%260%5Cend%7Barray%7D%5Cright%5D)
To find the product AB and BA
AB=![\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%26-5%5C%5C-3%26-4%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%20%26%20-1%5C%5C-3%20%260%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B15%26%20-6%2B0%5C%5C-3%2B12%263-0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of AB is
AB=
BA=
![=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%2B3%26%20-5%2B4%5C%5C-18%2B0%2615%2B0%5Cend%7Barray%7D%5Cright%5D)
Therefore the product of BA is
BA=
The products of AB and BA is given by
AB=
BA=
The word will depend on how many equal shares there are. For example, if there are two equal shares, you can say "halves"; if there are three equal shares, you can say "thirds"; if there are four equal shares, you can say "quarters," etc.
Answer:
The answer is ± 5<em>i</em>
No it doesn't , I agree with him
