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Brrunno [24]
3 years ago
8

7. Change the fraction 13/20 to a decimal.

Mathematics
2 answers:
Contact [7]3 years ago
5 0

Answer:

divide it using a calculator

Nady [450]3 years ago
3 0

Answer:

Step-by-step explanation:

0.65 is your answer

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3 years ago
Simplify this please 41 =12d-741=12d−7
Maurinko [17]

Answer:

Simplifying

41 = 12d + -7

Reorder the terms:

41 = -7 + 12d

Solving

41 = -7 + 12d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-12d' to each side of the equation.

41 + -12d = -7 + 12d + -12d

Combine like terms: 12d + -12d = 0

41 + -12d = -7 + 0

41 + -12d = -7

Add '-41' to each side of the equation.

41 + -41 + -12d = -7 + -41

Combine like terms: 41 + -41 = 0

0 + -12d = -7 + -41

-12d = -7 + -41

Combine like terms: -7 + -41 = -48

-12d = -48

Divide each side by '-12'.

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d = 4

3 0
3 years ago
You require space to serve 65 vehicles at any one time. Will a facility measuring 145ft by 130ft be adequate if each vehicle req
Hunter-Best [27]

Answer: No, it is not sufficient to serve 65 vehicles as it can only serve 62 vehicles with this space

Step-by-step explanation:

Since we have given that

Dimensions of space where vehicles are stored is

145 feet by 130 feet

Number of vehicles to serve = 65

Area required for each vehicle = 300 ft²

So, we need to find that is it sufficient for to serve 65 vehicles.

So, first we find the number of vehicles can be served in this space

\text{ Number of vehicles}=\frac{\text{ Area of space}}{\text Area of space required for one vehicle }}\\\\=\frac{145\times 130}{300}\\\\=\frac{18850}{300}\\\\=62.83\\\\=62\ approx

No, it is not sufficient to serve 65 vehicles as it can only serve 62 vehicles with this space.

6 0
3 years ago
Read 2 more answers
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