A. Box Plot because the box plot gives the 5 number summary
You can figure this out if you just look at (x+a)^2 = x^2 + 2ax + a^2. See, the constant term, a^2, is the coefficient of x (2a), divided by 2 (2a/2=a), and then squared (a^2)
<span>So you equation has 8x. 8/2 = 4, and 4^2 = 16. So the answer is A.</span>
Log10 (6/5)^6
= 6 log10 (6/5)
= 6 (log10 6 - log10 5) Answer
Answer:

Step-by-step explanation:
Given
See attachment for model
Required
Determine
from the model
The model is represented by:

To get:
, we consider the first partition
The number of shaded box is 63 ---- this represents the denominator
The total boxes shaded at the bottom is 36 ---- this represents the numerator
So, we have:

To get:
, we consider the first partition
The number of shaded box is 63 ---- this represents the denominator
The total boxes shaded at the bottom is 16 (do not count the gray boxes) ---- this represents the numerator
So, we have:

The equation becomes:




Answer:
The sum of first 50 terms is 3425.
Step-by-step explanation:
Let the first tem of A.P be 'a' and it's common difference be 'd'
Thus the 16th term of the A.P is given by

Now we know that the sum of first 'n' terms of the A.P is given by
![S_n=\frac{n}{2}[2a+(n-1)d]\\\\5=\frac{5}{2}[2a+4d]\\\\1=a+2d..........(ii)](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D%5C%5C%5C%5C5%3D%5Cfrac%7B5%7D%7B2%7D%5B2a%2B4d%5D%5C%5C%5C%5C1%3Da%2B2d..........%28ii%29)
Solving equation 'i' and 'ii' simultaneously we get

Thus 
Thus the sum of first 50 terms euals
![S_{50}=\frac{50}{2}[2\times -5+(50-1)3]\\\\S_{50}=3425.](https://tex.z-dn.net/?f=S_%7B50%7D%3D%5Cfrac%7B50%7D%7B2%7D%5B2%5Ctimes%20-5%2B%2850-1%293%5D%5C%5C%5C%5CS_%7B50%7D%3D3425.)