We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Round 125.6 to the nearest 10th
1 answer:
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Answer:
−438°, -78°, 642°
Step-by-step explanation:
Given angle:
282°
To find the co-terminal angles of the given angle.
Solution:
Co-terminal angles are all those angles having same initial sides as well as terminal sides.
To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°
So, we have:
To find the negative co-terminal of an angle between 0° to -360° we add it to -360°
So, we have:
To find the negative co-terminal of an angle between -360° to -720° we add it to -720°
So, we have:
Thus, the co-terminal angles for 282° are:
−438°, -78°, 642°