Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = 
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer:
3t+2
Step-by-step explanation:
First, we focus on the part with the "t" variable. Then we subtract the values with variables which gets us 3t. Finally, we can't do anything with the +2, so our solution is 3t+2.
1: m=-4
2: b=-4
3: -9=k
4: C=-11.4
5:X<10
Answer:
3 cups
Step-by-step explanation:
I can’t see it is too burly I’m Srry