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Lera25 [3.4K]
3 years ago
12

Simplify the rational expression. state any restrictions on the variable. n^4-11n^2+30/n^4-7n^2+10

Mathematics
1 answer:
Andrej [43]3 years ago
7 0
<span>For this case we have the following expression:
</span> \frac{n ^ 4-11n ^ 2 + 30}{ n ^ 4-7n ^ 2 + 10} &#10;&#10;
<span> We are going to make the following change of variables:
 </span>x = n ^ 2&#10;
 <span>Rewriting the expression we have:
 </span>\frac{(x ^ 2-11x + 30)}{(x ^ 2-7x + 10)} &#10;&#10;
 <span>Factoring the expression we have:
 </span>\frac{(x-5) (x-6)}{(x-5) (x-6)} &#10;
 <span>Canceling similar terms we have:
 </span>\frac{x-6}{x-2} &#10;
 <span>Returning the change we have:
 </span>\frac{n ^ 2-6}{n ^ 2-2} &#10;&#10;
<span> The resctrictions of the function are those that make the denominator equal to zero.
 We have then:
 </span>n ^ 2-2 = 0&#10;&#10;n = +/-  \sqrt{2} &#10;
<span> Answer:
 The simplified expression is:
 </span>\frac{n ^ 2-6}{n ^ 2-2}
 <span>The restrictions are:
 </span>n = \sqrt{2} &#10;
 n = -  \sqrt{2}
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3 years ago
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What is the mass of 2.5 moles of carbon dioxide?
GarryVolchara [31]

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

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