How do you solve this: 2y^2=x+4
1 answer:
To solve this for an equation that you can graph, you need to isolate the y variable. In order to do this, follow the order of operations for solving equation to get the equation.
2y^2 = x + 4 ----> divide both sides by 2
y^2 = ----> take the square root of both sides
y =
Now you have the equation solved for the y variable and can graph it.
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Answer:
Second point (-5/2, -7/2)
First point (3/2, 17/2)
Step-by-step explanation:
We have two equations, and we want to know at wich poin are equal. Hence, we have a system of equations and the solution is nothing more that the point (x,y) where those functions intercepts.
4x2+ 7x -11=y
3x+4=y
Lets use substitute method
4x2+7x-11=3x+4
This can be re arrange as the following eq:
4x2+4x-15=0
A quadratic equation, its solution can be obtained using the below eq.
where a=4, b=4, c=-15.
Remember, the quadratic equation as a +/- sign, meaning that you will obtain one answer using the + operator and other using the - operator.
By doing the above, we have x=-5/2 and x=3/2
By using x=3/2 in equation of line (3x+4=y) we have y=17/2
First point (3/2, 17/2)
By using x=-5/2 in equation of line (3x+4=y) we have y= -7/2
Second point (-5/2, -7/2)
Those points are the ones where the line and the parabola intercept.
Answer:
answer is 89.23.I hope this answer will help you
