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3 years ago

I don’t understand how to solve this : -17 + 18 - 12

Mathematics

2 answers:

Mademuasel [1]3 years ago

8 0

$\text{Hey there!}$

$\text{Keep this in mind:}$

$\text{- and - = +}\\\text{- and + = -}\\\text{+ and + = +}\\\text{+ and - = -}$

$\text{Now, that we know that.. we know our answer will be a negative.}$

$\bf{-17 + 18-12}$

$\bf{-17 +18 =1}$

$\bf{1 - 12 = answer.}$

$\bf{1 - 12 = -11}$

$\boxed{\boxed{\bf{Answer: -11}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

Llana [10]3 years ago

6 0

Answer:

-11

Step-by-step explanation:

-17+18-12=x

1-12=x=-11

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Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

#learnwithBrainly

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3 years ago