1<br> f(x) =1/10x-4 g(x)=1/x+2

Can someone please answer 5, 6 and 7? Thank you.

Montano1993 [528]

Reduce a 24 cm by 36 cm photo to 3/4 original size.

The most logical way to do this is to keep the width-to-height ratio the same: It is 24/36, or 2/3. The original photo has an area of (24 cm)(36 cm) = 864 cm^2.

Let's reduce that to 3/4 size: Mult. 864 cm^2 by (3/4). Result: 648 cm^2.

We need to find new L and new W such that W/L = 2/3 and WL = 648 cm^2.

From the first equation we get W = 2L/3. Thus, WL = 648 cm^2 = (2L/3)(L).

Solve this last equation for L^2, and then for L:

2L^2/3 = 648, or (2/3)L^2 = 648. Thus, L^2 = (3/2)(648 cm^2) = 972 cm^2.

Taking the sqrt of both sides, L = + 31.18 cm. Then W must be 2/3 of that, or W = 20.78 cm.

Check: is LW = (3/4) of the original 864 cm^2? YES.

6 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

Adam works at a bakery. He uses 1/8 of his flour supply to make bread and 3/4 of his flour supply to make other baked goods. If

kykrilka [37]

Answer: B

he has 24 in his supply!

Step-by-step explanation:

7 0

3 years ago

Find the equation of the line by given two points (-5, -2) and (1, 5). Slope

docker41 [41]

Answer:

The equation of the line is 6y = 7x + 23

Step-by-step explanation:

We begin by calculating the slope of the line;

mathematically, the slope is given by;

m = (y2-y1)/(x2-x1)

That would be;

m= (5-(-2))/(1-(-5))

m = 7/6

So the equation becomes;

y = 7/6x + b

We below need to get the value of the y-intercept b

We get this by making a substitution for any of the two points

Let’s say we make the substitution for (-5,-2) in which case y = -2 and x = -5

Thus, we have

-2 = 7/6(-5) + b

-2 = -35/6 + b

b = -2 + 35/6

b = (-12+ 35)/6 = 23/6

So we have;

y = 7/6x + 23/6

let’s multiply through by 6

6y = 7x + 23

7 0

3 years ago

Choose all true statements.

serious [3.7K]

Answer:

Some rational numbers are natural numbers

All whole numbers are integers

Some integers are natural numbers.

Step-by-step explanation:

3 0

4 years ago

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1 f(x) =1/10x-4 g(x)=1/x+2