3 years ago

Write a decimal where the value of a digit is one tenth as much as a digit in another place

Mathematics

1 answer:

GenaCL600 [577]3 years ago

7 0

1.2 could be your answer

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35 61 63 69 49 46 52 32 34 50<br> what is the mode

egoroff_w [7]

Answer:

no mode

Step-by-step explanation:

Mode is the most common number shown therefore....

since there are no numbers repeated, the answer is no mode

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14. Find the solution of the initial value problem y′′ + y = F(t), y(0) = 0, y′(0) = 0, where F(t) = ⎧⎪⎨⎪⎩ At, 0≤ t ≤ ????, A(2?

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Justin has 750 more than Eva and Eva has 12 less than Justin together they have a total of 63 how much money did

lakkis [162]

Are you searching for how much Eva has or Justin?

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3 years ago

2+2 is 4 minus 1 that’s 3 quick maths

mr_godi [17]

Answer:

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Step-by-step explanation:

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Read 2 more answers

Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

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3 years ago