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2 years ago

120% of the sum of w and one- twelfth u

1 answer:

soldier1979 [14.2K]2 years ago

3 0

In this problem, you are asked to translate this verbal expression into algebraic expression. Then you must simply this expression if possible.So for this problem, the algebraic expression is:

1.2 ( w + u / 12) -> so simplifying this, will give us:

= 1.2w + 1.2*u/12

= 1.2w + u/10 would be the answer.

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Charlie Carr has a sheet of brass that is 33 inches wide and cuts two pieces that are each 8

denis-greek [22]

Answer: The width of the leftover brass is 17 inches.

Step-by-step explanation:

Hi, to answer this question, first, we have to add the width of the pieces cut.

Mathematically speaking:

8 in +8 in = 16 in

Now, we have to subtract that result to the width of the sheet of brass.

33 in -16 in = 17 in

The width of the leftover brass is 17 inches.

Feel free to ask for more if needed or if you did not understand something.

5 0

2 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

2 years ago

Help I don’t get it..

yan [13]

Answer:

Step-by-step explanation:

the shape looks like a cube.. and maybe they say something about that outside of the picture, even but assuming that it is a cube, we know all the sides are the same.

we also know that the area of one side of the cube is 3 $\frac{1}{4}$

so multiply that

W x L = area

3 $\frac{1}{4}$ * 3 $\frac{1}{4}$ = area

10 $\frac{9}{16}$ = area

10.5625 = area

those two answer above are the same .. just one is in fractions and one is in decimals

there are 6 sides on a cube, so multiply the above answer by 6

6* answer = 63.375

63 $\frac{3}{8}$ ( this is your answer)

both of those are also identical , but look different for the reasons I mentioned above

use which ever from seems better to you. :)

8 0

2 years ago

A Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of

ANEK [815]

Answer:

Since Family's Financial Situation and Religion seem more of a Family Discussion, I would round 46% to 50%. Then 37% to 40%. Add 50% and 40% and you'll get 90%.

Step-by-step explanation:

And by percent confidence level, I hope you're talking about mine...I would say 99% confidence level....lol

8 0

2 years ago

Please answer correctly !!!!!!!!!!!!!! Will Mark Brianliest !!!!!!!!!!!!!!!!!!!

alexgriva [62]

Answer:

x = 30

Step-by-step explanation:

well from the theorem we have

$\frac{15}{3}=\frac{x}{6}$