1) Identity Property of addition
2) Commutative Property of Multiplication
3) Zero property of multiplication
4) Commutative property of addition
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Answer:
(8-(4*2)) / 1 =0
Step-by-step explanation:
(8-(4*2)) / 1 =0
0.10×16,050+0.28×(134,899−16,050)
=34,882.72
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Farrah's total score for both rounds will be -3.
Since the leader board shows Farrah's score as 5 on the front nine, this will be: +5
Since the leader board shows Farrah's score as 8 on the back nine, this will be -8. Then we'll add both together to get the total score which will be:
= 5 + (-8)
= 5 - 8
= -3
His total score will be -3.
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