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Delvig [45]
3 years ago
10

If a (-1-3) and b (11-8) what is the length of an?

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0
It should be 10-5. Good luck!
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An electrician has a piece of wire that is 18 feet long. He cuts off 14% of the wire. Then he cuts the remaining pieces of wire
Ronch [10]

Answer:

the 3 pieces are 5.16ft each and the 14% that he cut off is 2.52 ft

Step-by-step explanation:

the 14 % that he cut off is 2.52ft

he has 15.48ft left

15.48/3=5.16

6 0
3 years ago
Jamal made a list of fractions and asked will to find the fraction written is simplest form.
viva [34]
I haven’t got there yet sorry
5 0
4 years ago
At a bus station, buses begin their routes at 6.am. The schedule for two of the buses is based on time intervals listen below-
Anastaziya [24]

Answer:

Part A: The two buses leave the bus station at 7 : 15 am

Part B: The steamboat travels 25 miles per hour

Step-by-step explanation:

* Lets explain how to solve the problem

<u><em>Part A</em></u>

- Buses begin their routes at 6 am at a bus station

- Bus A leaves every 75 minutes

- Bus B leaves every 15 minutes

- We want to know the next time Bus A and Bus B will leave the bus

  station at the Same time

# Bus A

∵ Bus A leaves every 75 minutes

- Lets change 75 minutes to hours and minutes

∵ 1 hour = 60 minutes

∴ 75 minutes = 75/60 = 5/4

- Change 5/4 to mixed number

∵ 5/4 = 1 1/4

∴ 75 minutes = 1 1/4 hours

- Lets change 1/4 hour to minutes

∴ 1/4 × 60 = 15 minutes

∴ 75 minutes = 1 hour and 15 minutes

∵ Bus A leaves the station at 6 am

- Add 1 hour and 15 minutes to that time

∵ 6 + 1 : 15 = 7 : 15

∴ Bus A leaves the station nest time at 7 : 15 am

# Bus B

∵ Bus B leaves every 15 minutes

∵ Bus B leaves the station at 6 am

- Add 15 minutes to 6 am

∴ Bus B leaves the station next time at 6 : 15 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 6 : 30 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 6 : 45 am

- Add another 15 minutes for next time

∵ 15 + 45 = 60 ⇒ add 6 by 1 because 60 minutes = 1 hour

∴ Bus B leaves the station next time at 7 am

- Add another 15 minutes for next time

∴ Bus B leaves the station next time at 7 : 15 am

- The 2 buses leave the station at the same time again at 7:15 am

* The two buses leave the bus station at 7 : 15 am

<em><u>Part B</u></em>

- It takes a steamboat 12 hours to travel 300 miles

- We need to find how many miles it travels per hour

∵ The steamboat travels 300 miles in 12 hours

- Divide the distance by the time to find its rate

∵ 300 ÷ 12 = 25

- That means it travels 25 miles per hour

∴ The steamboat travels 25 miles per hour

3 0
4 years ago
Which components are a possible representation of vector w if the magnitude of vector -3w is ||-3w||=15?
Black_prince [1.1K]

Answer:

<-3,4>

<0,-5>

Step-by-step explanation:

|-3w| = 15

3|-w| = 3|w| = 15

|w| = \frac{15}{3}

|w| = 5

  • If vector w is represented by <1,-9>

Then |w| = \sqrt{(1)^{2}+(-9)^{2}}=\sqrt{1+81}=\sqrt{82}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-3,4>

Then |w| = \sqrt{(-3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5 .

Therefore this is possible.

  • If vector w is represented by <4,5>

Then |w| = \sqrt{(4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-5,-3>

Then |w| = \sqrt{(-5)^{2}+(-3)^{2}}=\sqrt{25+9}=\sqrt{34}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <0,-5>

Then |w| = \sqrt{(0)^{2}+(-5)^{2}}=\sqrt{0+25}=\sqrt{25}=5 .

Therefore this is possible.

(NOTE : if z vector is represented by <x,y> then |z| = \mathbf{\sqrt{x^{2}+y^{2}}} )

4 0
3 years ago
Nevermind thank you
mote1985 [20]

Answer:

ok :)

Step-by-step explanation:

7 0
3 years ago
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