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lisov135 [29]
2 years ago
14

Directions: Solve the following system by the elimination method. 1/5 * x + y = 6/5; 1/10 * x + 1/3 * y = 7/10 Write answer as a

coordinate point. Need help asap
Mathematics
2 answers:
sattari [20]2 years ago
6 0

Answer:

i dont know sorry

Step-by-step explanation:

frosja888 [35]2 years ago
3 0

Step-by-step explanation:

Solve by the elimination method

x/5 + y = 6/5

x/10 + y/3 = 7/10

x + 5y = 6 |×2| 2x + 10y = 12

3x + 10y = 21 |×1| 3x + 10y = 22

__________ -

-x = -10

x = 10

x + 5y = 6

10 + 5y = 6

5y = 6 - 10

5y = -4

y = -4/5

Solution → (x,y) = (10 , -4/5)

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1/8

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To simplify the expression √3/√8, we can first simplify the square root terms by finding the prime factorization of each number under the square root. The prime factorization of 3 is 3, and the prime factorization of 8 is 2 * 2 * 2.

We can then rewrite the square root terms as follows:

√3/√8 = √(3) / √(2 * 2 * 2)

Next, we can use the property of square roots that says that the square root of a number is equal to the square root of each of its prime factors. This means that we can rewrite the square root term as follows:

√(3) / √(2 * 2 * 2) = √(3) / √(2) / √(2) / √(2)

Since the square root of a number is the same as the number itself, we can simplify the expression further by removing the square root symbols from the prime numbers 2:

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√(3) / (2 * 2 * 2) = 1/2 * 1/2 * 1/2 = 1/8

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