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photoshop1234 [79]
3 years ago
8

At the start of 2014 lucy’s House was worth £200,000. the value of the house increased by 5% every year . Work out the value of

her house at the start of 2017That’s the start of 2014 Lucy’s house was worth £200,000 the value of the house increased by 5% every year work out the value of her house at the start of 2017
Mathematics
2 answers:
julia-pushkina [17]3 years ago
7 0

Answer:

At start of 2017 house worth = $231,525

Step-by-step explanation:

To find the new value worth of the house in each year, you add the increase in worth of house in the preceding year and the worth of the house in the preceding year. How do I learn

At start of 2014 house worth = $200,000

At start of 2015 house worth = 2014 house worth + 5% of 2014 house worth

At start of 2015 house worth = $200,000 + 5% of 200,000

= 200,000 + 5/100 * 200,000

= 200,000 + 10,000 = $210,000

At start of 2015 house worth = $210,000

At start of 2016 house worth = 2015 house worth + 5% of 2015 house worth

At start of 2016 house worth = $210,000 + 5% of 210,000

= 210,000 + 5/100 * 210,000

= 210,000 + 10,500 = $220,500

At start of 2016 house worth = $220,500

At start of 2017 house worth = 2016 house worth + 5% of 2016 house worth

At start of 2017 house worth = $220,500 + 5% of 220,500

= 220,500 + 5/100 * 220,500

= 220,500 + 11,250 = $231,525

At start of 2017 house worth = $231,525

MAVERICK [17]3 years ago
5 0

By the end of 2014, the value was 210,00

By the end of 2015, the value was 220,00

By the end of 2016, the value was 230,00

Lastly, by the end of 2017, the value was 240,000

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
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The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

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So by using zero product property we will get

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t-7+7 = 0+7

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So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

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t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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