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d1i1m1o1n [39]
3 years ago
13

michelle bought the same fabric on 3 different occasions and recorded the data below what was the price per yard of fabric? answ

er
Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Please consider the complete question.

Michelle bought the same fabric on 3 different occasions and recorded the data below.

Yards of Fabric         Total Cost

2.2                             $2.53

3.6                             $4.14

4.2                             $4.83

What was the price per yard of fabric?

To find the cost per yard of fabric, we will divide cost of yards by number of yards.

\text{Cost per yard}=\frac{\text{Cost}}{\text{Number of yards}}

\text{Cost per yard}=\frac{\$2.53}{2.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Let us find cost per yard using 2nd set of data.

\text{Cost per yard}=\frac{\$4.14}{3.6\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Similarly we will find cost per yard for 3rd set of data.

\text{Cost per yard}=\frac{\$4.83}{4.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Therefore, the cost per yard of fabric is $1.15.

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Answer:

f'(x) = -28 \ at  \ x = 2

Step-by-step explanation:

f'(2) =  \lim_{h \to 0}\frac{f(2+h)) -f(2)}{h} \\\\f(2+h) = 1 - 7(2+h)^2 = 1 - 7(4 +h^2 +4h) = 1 - 28 - 7h^2 - 28h = - 7h^2 -28h - 27\\\\f(2) = 1 - 7(2^2) = 1 - 28 = -27\\\\f(2+h) - f(2) = -7h^2 - 28h - 27 - (-27) = -7h^2 -28h -27 + 27 = -7h^2 -28h\\\\f'(2) =   \lim_{h \to 0}\frac{-7h^2 - 28h}{h} \\\\

       = \lim_{h \to 0} \frac{h(-7h -28)}{h}\\\\= \lim_{h \to 0} (-7h -28)}\\\\= -7 (0) - 28\\\\= -28

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You were testing orange juice recipes it’s recipe calls for orange juice concentrate and water mix one has 4 cups of concentrate
Sav [38]

Answer:

First mixed is the most orangey.

Step-by-step explanation:

First:

Orange\ juice\ concentrate=4\ cups\\\\Water=6\ cups\\\\Tota\ content=4+6=10\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{4}{10}\times 100=40\%

Second:

Orange\ juice\ concentrate=1\ cups\\\\Water=3\ cups\\\\Tota\ content=1+3=4\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{1}{4}\times 100=25\%

Third:

Orange\ juice\ concentrate=2\ cups\\\\Water=4\ cups\\\\Tota\ content=2+4=6\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{2}{6}\times 100=33.33\%

First mixed has highest percentage of orange juice. Hence first mixed is the most orangey.

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3 years ago
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