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Svetach [21]
3 years ago
13

What is the common ratio in the following geometric sequence?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Hey there!


A common ratio is just that number that you multiply or divide to each number that gets you the next in a geometric sequence. In this sequence, we know the numbers are getting bigger and we're multiplying, so we want to know what you're multiplying by the first number to get to the second. We can call this unknown number x. SO if we start with the first number and set up an equation, we get:


3x = 12


Divide both sides by 3


x = 4


Therefore, your common ratio is 4.


To check, you can multiply all the next numbers by 4 to see that it all checks out.


Hope this helps!

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The weekly earnings of students in one age group are normally distributed with a standard deviation of 47 dollars. A researcher
ELEN [110]

Answer:

Option D) 340

Step-by-step explanation:

We are given the following in the question:

Alpha, α = 0.05

Population standard deviation, σ = $47

Margin of error = 5

95% Confidence Interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

\text{Margin of error} = z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

5 = 1.96(\dfrac{47}{\sqrt{n}} )\\\\\sqrt{n} = \dfrac{47\times 1.96}{5}\\\\n = 339.443776\\\Rightarrow n \approx 340

Thus, the correct answer is

Option D) 340

7 0
3 years ago
Search cos jk and tan jk knowing that sin jk = 8/3
aleksley [76]

Answer:

cosjk = √55 i/3

tanjk = 8/√55 i

Step-by-step explanation:

Given

sin jk = 8/3

According to SOH CAH TOA

Sin theta = opposite/hypotenuse = 8/3

Opposite = 8

hypotenuse = 3

Get the adjacent using the pythagoras theorem

hyp² = opp²+adj²

adj² = hyp² - opp²

adj² = 3² - 8²

adj² = 9-64

adj² = -55

adj = √-55

adj = √55 i (i = √-1)

Get cosjk

cosjk = adj/hyp

cosjk = √55 i/3

Get tanjk

tanjk = opp/adj

tanjk = 8/√55 i

3 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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What is the volume of a pentagonal prism that has a base area of 5.16 cm2 and a height of 9 cm?
strojnjashka [21]
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Have fun!
4 0
3 years ago
Read 2 more answers
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