It is a linear equation so there can be 1 solution, 0 solutions, or infinite solutions
4(x-5)=4x-24
distribute
4x -20 = 4x-24
subtract 4x from each side
-20 = -24
no solutions
Answer:
f(g(-64)) = -190
Step-by-step explanation:
The functions are not well written.
Let us assume;
f(x) = x+1
g(x) = 3x+1
f(g(x)) = f(3x+1)
Replace x with 3x+1 in f(x)
f(g(x)) = (3x+1) + 1
f(g(x)) = 3x + 2
f(g(-64)) = 3(-64) + 2
f(g(-64)) = -192+2
f(g(-64)) = -190
<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
Answer:
7x + 6 = 6x - 3
Step-by-step explanation:
2(x+3) + 5x = 3(2x-1)
Distribute
2x + 6 + 5x = 6x - 3
Combine like terms
7x + 6 = 6x - 3
hope this helps
