Answer:
In general, we already know how to solve problems in a right triangle using the concept of trigonometry. Meanwhile, as we also know that the type of triangle is not only a right triangle, but there are isosceles, equilateral, or even random triangles. The question is how to solve the problems that exist in these triangles It is known that there is an arbitrary triangle with sides a, b, and c. The angle formed in front of side a is called angle α, the angle formed in front of side b is called angle β, and the angle formed in front of side c is called angle γ = 5
Step-by-step explanation:
x" + 5x + 6 = 0
(x + 2)(x + 3) = 0
x + 2 = 0
x = -2
x + 3 = 0
x = -3
#semogamembantu
Answer:
g(x) = x² + 5x + 2
Step-by-step explanation:
If a function is f(x) = x²
And this function is shifted 4 units left then the rule to be followed is,
g(x) = f(x + 4)
Following the same rule,
For a function f(x) = x² - 3x - 2 when shifted 4 units to the left,
g(x) = f(x + 4)
g(x) = (x + 4)² - 3(x + 4) - 2
= x² + 8x + 16 - 3x - 12 - 2
= x² + 5x + 2
Therefore, g(x) = x² + 5x + 2 will be the transformed function.
Our goal is to isolate the variable, which is b. What you do to one side must also be done to the other side since we need to maintain equality.
Add 1 to both sides
b/5=11
Then multiply both sides by 5
b=55
Final answer: b=55
F(x) = 3x^2 + 4x - 1
f(-3) = 3(-3)^2 + 4(-3) - 1
f(-3) = 3 * 9 - 12 - 1
f(-3) = 27 - 12 - 1
f(-3) = 15 - 1
f(-3) = 14