Answer: F
Step-by-step explanation:
This is basically like 2 rectangles. Find the area of both and add them together.
Remember that the area is
x
.
Area of Rectangle 1:
= 7,
= 14
14 x 7 = 98![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Area of Rectangle 2:
= 5,
= 14
14 x 5 = 70![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Add the areas together: 98
+ 70
= 168![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Conversion factor: 1 pint = 0.5 quarts or 2 pint = 1 quart
multiplying both sides by 8
8(1 quart) = 8 (2 pints)
8 quarts = 16 pints
so she will need a total of 16 pints to fill the pot. she already has 1 so... 16 - 1 = 15 more pints.
and looking at the 1st conversion factor 1 pint = 0.5 quarts
15 (1 pint) = 15 (0.5 quart)
15 pints = 7.5 quarts
Answer:
see below
Step-by-step explanation:
Significant figures are numbers that are necessary to express a true value.
Place the values in scientific notation.
Explaining <u>why</u>
1. The zero that is within 5.6803 is "trapped," meaning it is in between two nonzero digits. Therefore, all five digits are significant figures.
2. The zeroes that precede the 4 and the 7 are not significant because they are dropped in scientific notation and are not trapped by other nonzero digits. Therefore, only two digits of this value are significant.
3. Because the zero at the end of 0.240 is a trailing zero, it is significant along with the 2 and the 4. The zero that precedes these digits and the decimal point is not significant. Therefore, only three digits of this value are significant.
Hope this helps! :)
![\mathbf J=\begin{bmatrix}\dfrac{\partial x}{\partial u}&\dfrac{\partial x}{\partial v}\\\\\dfrac{\partial y}{\partial u}&\dfrac{\partial y}{\partial v}\end{bmatrix}=\begin{bmatrix}2u+v&u\\v^2&2uv\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathbf%20J%3D%5Cbegin%7Bbmatrix%7D%5Cdfrac%7B%5Cpartial%20x%7D%7B%5Cpartial%20u%7D%26%5Cdfrac%7B%5Cpartial%20x%7D%7B%5Cpartial%20v%7D%5C%5C%5C%5C%5Cdfrac%7B%5Cpartial%20y%7D%7B%5Cpartial%20u%7D%26%5Cdfrac%7B%5Cpartial%20y%7D%7B%5Cpartial%20v%7D%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D2u%2Bv%26u%5C%5Cv%5E2%262uv%5Cend%7Bbmatrix%7D)
The Jacobian has determinant