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3 years ago

This is due very soon I'm so lost please help

Mathematics

1 answer:

Oksanka [162]3 years ago

5 0

Ill try to assist you with these

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Two weeks in a row, the golf course hosts a group of golfers. The second week had 10 more golfers than the first week. Use the d

Trava [24]

Answer:

Option A.

Step-by-step explanation:

From the first dot plot the given data set for week 1 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69), (70, 70, 72, 72, 72), (75, 75, 76, 78, 78), (80, 80, 80, 89, 89)

$Range=Maximum-Minimum=89-62=27$

$Median=\frac{72+75}{2}=73.5$

$Mean=\frac{\sum x}{n}=\frac{1491}{20}=74.55$

From the second dot plot the given data set for week 2 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 85, 86, 86, 86, 88, 88, 88, 88, 89, 89, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69, 70, 70), 72, (72, 72, 75, 75, 76, 78, 78), (80, 80, 80, 85, 86, 86, 86), 88, (88, 88, 88, 89, 89, 89, 89)

$Range=Maximum-Minimum=89-62=27$

$Median=\frac{78+80}{2}=79$

$Mean=\frac{\sum x}{n}=\frac{2364}{30}=78.8$

The range for Week 1 is equal to the range for Week 2.

The median for Week 2 is more than the median for Week 1.

The mean for Week 2 is more than the mean for Week 1.

Therefore, the correct option is A.

6 0

3 years ago

HELPPP I HAVE EXAM WITH TIIME PLEASE HELP MEEEE IM LOSTT

Scilla [17]

A) Her total pay is $3120
b) She sold 33 copies

4 0

3 years ago

In a class 22 of students, 14 have a brother and 9 have a sister. There are 2 students who do not have any siblings. What is the

djyliett [7]

I believe this is the way to solve it.
22 - 2 = 20
20 is 90.9% of 22
So the probability of choosing a student with a sibling at random should be 90.9% (or you can round up to 91%)

I hope this helps :)

5 0

4 years ago

Please help! Best answer gets Brainliest!

Elanso [62]

Answer:

pretty sure its B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If a parabola had a y-intercept of (0,5) and an axis of symmetry at x = 4, what other point must be on the graph? (hint: draw)

Serga [27]

Answer:

(8, 5)

Step-by-step explanation:

Let's take a look at the y-intercept, (0, 5). If the axis of symmetry is x = 4, then the distance from (0, 5) is 4 units. If we reflect this point (0, 5) about the axis of symmetry x = 4, the resulting point is (8, 5). In other words, the distance from the y-intercept to the axis of symmetry is 4 units, and so the distance from the y-intercept must be 4 units plus 4 units, or 8 units.

The only answer choice that matches this is the second one: (8, 5).

3 0

3 years ago