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3 years ago

If the greatest possible error of a measurement is 1/32 inches, what is the actual precision of this measurement?

Mathematics

1 answer:

Rus_ich [418]3 years ago

3 0

Answer:

1/16 in

Step-by-step explanation:

The largest possible error in representing a number is half the unit of precision. Here, the error is said to be 1/32 in. That is half of 1/16 in. So, the unit of precision must be 1/16 in.

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Over the first five years of owning her car, Gina drove about 12,700 miles the first year, 15,478 miles the second year, 12,675

kvv77 [185]

Answer:

Part a)

Mean: 13155.6

Mode:None

Median: 12700

Step-by-step explanation:

12700 : 1

15478: 2

12675: 3

11850: 4

13075: 5

Mean :

$=\frac{Sum of all values}{Total no. of values} \\=\frac{12700 + 15478 + 12675 + 11850 + 13075}{5}\\=\frac{65778}{5}\\= 13155.6$

Mode:

All values are distinct, therefore there is no mode. A mode is value which occurs most frequently.

Median:

Arrange the values in ascending order:

11850 , 12675, 12700, 12075, 15478

The mid value is median: 12700

Part b)

It depends upon the data. In this question the best way to predict how many miles Gina will drive in the next years is by using Median of the data.

The reason is that there is a potential outlier in the data i.e 15478. In case of outlier median tends to give better predictions.

6 0

3 years ago

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Dennis_Churaev [7]

Yo get up bdbdndndbbd

4 0

3 years ago

How do you make $2.161616 as a fraction and a mixed number

tatuchka [14]

Essentially, if you want something repeating, you want a 9 in your denominator - 0.22 repeating would be 2/9 or 22/99 and 0.16 repeating would be 16/99. Therefore, 2+16/99 is a mixed number and (198+16)/99=214/99 as a fraction

6 0

3 years ago

Two friends practice taekwondo in the same class. The age of the older friend is three times that of the younger. The sum of the

vampirchik [111]

Answer:

4 and 12

Step-by-step explanation:

a = young

b = old

b = 3a, a+b =2a+8 => a = 4, b = 12

6 0

3 years ago

What is the sum of the infinite geometric series 9−6+4−83+...9-6+4-83+...??

vivado [14]

Successive terms have a common factor of $-\dfrac23$ , which means the $n$ th partial sum of the series can be written as

$S_n=9-6+4-\dfrac83+\cdots+9\left(-\dfrac23\right)^{n-1}$
$S_n=9\left(1+\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\cdots+\left(-\dfrac23\right)^{n-1}$

$\implies-\dfrac23S_n=9\left(\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\left(-\dfrac23\right)^4+\cdots+\left(-\dfrac23\right)^n\right)$

$\implies S_n-\left(-\dfrac23\right)S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$\dfrac53S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$S_n=\dfrac{27}5\left(1-\left(-\dfrac23\right)^n\right)$

As $n\to\infty$ , the geometric term vanishes, leaving you with

$S=\displaystyle\lim_{n\to\infty}S_n=\dfrac{27}5$

7 0

3 years ago