A loss in 2 points per forget, times 6 times forgetting gives 12. But since it is a deduction in points the final integer answer is -12
12 - t|3r - 2|
r = -6; t = 3
subtitute:
12 - 3 · |3 · (-6) - 2| = 12 - 3 · |-18 - 2| = 12 - 3 · |-20| = 12 - 3 · 20 = 12 - 60 = -48
Answer:
Jenny is wrong the correct answer is x²+ 4 - 4 x.
Step-by-step explanation:
Given that
(x-2)³∕x-2
(x-2)³∕(x-2) =(x-2) (x-2)²∕(x-2)
(x-2)³∕(x-2) = (x-2)²
As we know that
(a-b)² = a²+b² - 2 ab
So
(x-2)² = x²+ 2² - 2 ˣ 2 ˣ x = x²+ 4 - 4 x
(x-2)² = x²+ 4 - 4 x
It means that
(x-2)³∕(x-2) = (x-2)² = x²+ 4 - 4 x
So Jenny is wrong the correct answer is x²+ 4 - 4 x.
Since it’s a square we know that GJ has to be the same as GH. To find a diagonal you would do a^2 + b^2 = c^2. Which gives us about 9.19. So GJ=6.5 and JH=9.2
