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Annette [7]
3 years ago
6

Natural numbers are part of every other category of number except

Mathematics
2 answers:
marishachu [46]3 years ago
7 0

By definition, we have:

In mathematics, a natural number is any of the numbers that are used to count the elements of certain sets, as well as in elementary calculation operations. They are those natural numbers that serve to count elements so they are whole.

For example:

1,2,3,4,5,6,7,8,9 ... ∞

By conventional definition it will be said that any member of the next set, ℕ = {1, 2, 3, 4, ...}, is a natural number.

Integers, whole numbers, real numbers, include natural numbers.

Answer:

Natural numbers are part of every other category of number except:

B. irrational numbers.

avanturin [10]3 years ago
3 0

"Natural numbers" are the counting numbers ... one, two, three, seventy-two, etc.

They're the first group of numbers that children learn, and may well be the
most rational group of numbers you'll ever see.  One thing none of them is
is an irrational number.

           'B'.

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What is 48 square feet in square meters
Marina86 [1]

Answer: 4.45935

Step-by-step explanation: 1 Square foot (sqft) is equal to 0.09290304 square meter (sqm). For example, to convert 100 square feet to square meters, multiply 100 by 0.09290304, that makes 9.290304 sqm is 100 sqft. Hope this helps.

6 0
3 years ago
Solve for x I don't know how to solve it​
mixer [17]

Answer:

x=-12

Step-by-step explanation:

32+2x=6+x+14

2x-x=6+14-32

x=-12

ST=6

TU=-12+14=2

SU=6+2=8

8 0
3 years ago
Rewrite e^{x}= y into logarithmic form.
Aleksandr-060686 [28]

Answer:

x=\ln{y}

Step-by-step explanation:

The natural logarithm function is the inverse of the natural exponential function.  

\text{power}=\text{base}^{\text{exponent}}\\\\\text{exponent} \: =\: \log_\text{base}{\text{power}

are equivalent.

6 0
3 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
What metric measurement would be the most appropriate to measure the length of a horse?
motikmotik
Decimeters
plz tell me if im wrong
4 0
3 years ago
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