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DIA [1.3K]
3 years ago
8

Decide whether the sequence 4,10,20,34,52 ....... is a linear model,

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

Lineal.

Step-by-step explanation:

To determine if the sequence 4,10,20,34,52 ....... is a linear model, a quadratic model or a cubic model, the following mathematical logical reasoning must be carried out:

4 to 10 = +6

10 to 20 = +10

20 to 34 = +14

34 to 52 = +18

Thus, we can see at a glance that the sequence increases 4 numbers in each digit, adding first 6, then 10, then 14 and so on, with which the next numbers in that sequence should be 74 (+22), 100 ( +26), 130 (+30), 164 (+34), and so on.

Therefore, since there is no quadratic or cubic relationship, the sequence is linear.

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Can you simplify 5ths
aev [14]
You cannot simplify fifths because it is a prime number. Prime numbers are only divisible by 1 and itself.
6 0
3 years ago
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A certain flight arrives on time 8484 percent of the time. Suppose 143143 flights are randomly selected. Use the normal approxim
Troyanec [42]

Answer:

a) P(x=108)=0.0020

b) P(x≥108)=0.9980

c) P(x<124)=0.7794

d) P(124≤x≤128)=0.1925

Step-by-step explanation:

We know the population proportion, that is p=0.84.

We take a sample of size n=143.

We will use the normal approximation to the binomial distribution to model this problem.

The mean and standard deviation of the normal approximation to the binomial distribution will be:

\mu=np=143*0.84=120.12\\\\\sigma=\sqrt{np(1-p)}=\sqrt{143*0.84*0.16}=\sqrt{19.22}=4.38

a) We have to calculate the probability that exactly 108 flights are on time.

As the normal distribution considers the random variable to be continous, we have to apply the continuity correction factor.

In this case, the probability of 108 flights on time can be calculated as P(107.5<x<108.5):

P(x=108)=P(107.5

b) Now we have to calculate that at least 108 flights are on time.

As the probability includes 108, the continuity factor will indicates that we calculate P(x>107.5). The z-value for x=107.5 has been already calculated in point a:

P(x\geq108)=P(x>107.5)=P(z>-2.88)=0.9980

c) We have to calculate the probability that fewer than 124 flights are on time. According to the continuity factor, we have to calculate the probability P(x<123.5), as the flight number 124 is not included in the interval.

P(x

d) We have to calculate the probability that between 124 and 128 flights, inclusive, are on time.

This interval corresponds to the probability P(123.5<x<128.5)

P(123.5

5 0
3 years ago
Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,
Pepsi [2]
11t=120(12)

11t=1440

t=1440/11

However t is in hours and we want to know days so:

d=(1440/11)/24

d=1440/264

d=60/11

d=5 5/11 days
5 0
3 years ago
Read 2 more answers
Triangle ABC is congruent to triangle DFE. Find x.
diamong [38]
   Since congruent triangles are the exact same figures, then triangle ABC is the exact same shape as triangle DFE. Hence, as I don't have any additional information to find x, x would be the same for both figures.
5 0
3 years ago
Apples: $(2x) per pound
Ludmilka [50]

Answer:

Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges

Step-by-step explanation:

Cost of one pound of Apple = $2x

Cost of one pound of Grapes = $(6x-5)

Cost of one pound of Oranges = $(x+2)

A shopper purchases one pound each of  apples, grapes, and oranges and spends  $10.50.

It can be written as: 2x+6x-5+x+2=10.50

We need to find how much the shopper spend on each fruit.

First we need to find value of x by solving equation

2x+6x-5+x+2=10.50

Solving:

2x+6x+x+2-5=10.50\\9x-3=10.50\\9x=10.50+3\\9x=13.5\\x=\frac{13.5}{9}\\x=1.5

The value of x is: x=1.5

Now finding cost of one pound each fruit by putting x=1.5

Cost of one pound of Apple = $2x = 2(1.5) = $3

Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4

Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5

So,

Cost of one pound of Apple  = $3

Cost of one pound of Grapes = $4

Cost of one pound of Oranges = $3.5

So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges

3 0
3 years ago
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