Answer: The critical value = 21.920
And the rejection region for this type of chi-square test would be
![X^2> 21.92](https://tex.z-dn.net/?f=X%5E2%3E%2021.92)
Step-by-step explanation:
Since we have given that n = 12
'So, we first find the degrees of freedom.
So, degrees of freedom v = n-1 = 12-1 = 11
Now, α = 0.05
since it is two tailed test, so,
![1-\dfrac{\alpha }{2}\\\\=1-\dfrac{0.05}{2}\\\\=1-0.025\\\\=0.975](https://tex.z-dn.net/?f=1-%5Cdfrac%7B%5Calpha%20%7D%7B2%7D%5C%5C%5C%5C%3D1-%5Cdfrac%7B0.05%7D%7B2%7D%5C%5C%5C%5C%3D1-0.025%5C%5C%5C%5C%3D0.975)
So, using the table of chi square test, we get that
at v = 11, and 0.975,
Critical value = 21.920
Hence, the critical value = 21.920
And the rejection region for this type of chi-square test would be
![X^2> 21.92](https://tex.z-dn.net/?f=X%5E2%3E%2021.92)