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3 years ago

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Rosa purchase two chocolate bars and six ice cream bars for each of her five friends chocolate bars cost $3 each and eat ice cre

am bars W dollars each which expression represents the total amount Rose has been on her five friends?

1 answer:

Svet_ta [14]3 years ago

6 0

Answer:

3W

Step-by-step explanation:

You might be interested in

Algebraic fractions<br> x² + 5x+4 /<br> x²+ 4x + 3

Tresset [83]

Answer:

$\frac{x+4}{x+3}$

Step-by-step explanation:

Given

$\frac{x^2+5x + 4}{x^2+4x+3}$ ← factor numerator and denominator

= $\frac{(x+1)(x+4)}{(x+1)(x+3)}$ ← cancel common factor (x + 1) on numerator/ denominator

= $\frac{x+4}{x+3}$

8 0

3 years ago

Find the unknown side length x.

Ganezh [65]

Answer:

x = $\sqrt{65}$

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

$4^{2}$ + $7^{2}$ = $x^{2}$

16 + 49 = $x^{2}$

65 = $x^{2}$

x = sq rt 65

6 0

3 years ago

Someone answer this please

navik [9.2K]

Answer:

b = 33m is the answer

Step-by-step explanation:

a = 44m

b = ?

c = 55m

According to the Pythagoras theorem,

a² + b² = c²

44² + b² = 55²

1936 + b² = 3025

b² = 3025 - 1936

b² = 1089

b = 33m

∴ b = 33m is the length of the missing leg.

3 0

3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0

3 years ago

Can you divide fractions using models

igor_vitrenko [27]

Yes u can. It is very easy

7 0

3 years ago

Read 2 more answers