Hello from MrBillDoesMath!
Answer: 48.2 degrees
Discussion:
In the diagram, "6" is the x- distance along the side adjacent to theta, and
3 * sqrt(5) is the y-distance along the side opposite angle theta.
By definition of tangent of angle, using "@" for theta, we have
tan (@) = opposite/adjacent = 3 * sqrt(5) / 6 = sqrt(5)/2
So @ = (inverse tangent (sqrt(5)/2) ) = 48.189 degrees (approximately)
Thank you,
MrB
Answer:
Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)
P
=
(
x
1
,
y
1
,
z
1
)
to a plane determined by normal vector N=(A,B,C)
N
=
(
A
,
B
,
C
)
and point Q=(x0,y0,z0)
Q
=
(
x
0
,
y
0
,
z
0
)
. The equation for the plane determined by N
N
and Q
Q
is A(x−x0)+B(y−y0)+C(z−z0)=0
A
(
x
−
x
0
)
+
B
(
y
−
y
0
)
+
C
(
z
−
z
0
)
=
0
, which we could write as Ax+By+Cz+D=0
A
x
+
B
y
+
C
z
+
D
=
0
, where D=−Ax0−By0−Cz0
D
=
−
A
x
0
−
B
y
0
−
C
z
0
.
This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P
P
.
Step-by-step explanation:
Answer:
0 i guess
Step-by-step explanation:
Answer:
5 cups contain <u>7one-half pounds</u> of candy.
Step-by-step explanation:
Given:
Peter filled 5 cups each with 1one-half pounds of candy.
Now, to find the total candy 5 cups contain altogether.
1 cup of candy contain = 
So, to get candy 5 cup contain we multiply 5 by .
Therefore, 5 cups contain 7one-half pounds of candy.
