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Sphinxa [80]
3 years ago
14

How would you show you work for number 56?

Mathematics
2 answers:
Lynna [10]3 years ago
7 0
I guess she sold 84 cds out of 96:
84/96 = 0.875
IceJOKER [234]3 years ago
6 0
So you.will do 84/96 because she sell 84 CDs
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A climber is descending at a rate of 345 feet per hour. What is the climber's change in altitude after three hours of climbing?​
FromTheMoon [43]

Answer:

1035 feet in 3 hours

3 0
2 years ago
Asha makes a conjecture that the perimeter of a square whose sides are an odd integer is always even. Which choice is the best p
Ivan

Answer: Bottom left corner

Let n be an odd number. Because 4n is a multiple of 2, it is an even number.

============================================

Explanation:

The square has a side length of n, so its perimeter is 4n since n+n+n+n = 4n.

We can rewrite 4n as 2*2n = 2m where m = 2n is an integer. Any number in the form 2*(some integer) is always even. Even numbers always have 2 as a factor.

So whenever it comes to proving something is even, the ultimate goal is to get it into the form 2*(some integer). If we can do this, then the number is even. If not, then the number is odd.

4 0
2 years ago
Read 2 more answers
Determine each of the following.
castortr0y [4]

Answer:

(a) \{1,2,3,4,5,6,7,8,9,10\}

(b) 10

(c) \{\}

(d) 0

(e) 1024

Step-by-step explanation:

(a)

A = {x ∈ Z | 0 < x, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

0                ... (1)

x^2\leq 100

Taking square root on both sides.

-\sqrt{100}\leq x\leq \sqrt{100}

-10\leq x\leq 10             .... (2)

Using (1) and (2) we get

0

Since x ∈ Z,

A=\{1,2,3,4,5,6,7,8,9,10\}

(b)

We need to find the value of  | {x ∈ Z | 0 < x, x² ≤ 100}| or |A|. It means have to find the number of elements in set A.

|A|=10

| {x ∈ Z | 0 < x, x² ≤ 100}| = 10

(c)

B = {x ∈ Z | x > 10, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

x>10                ... (3)

x^2\leq 100

It means

-10\leq x\leq 10             .... (4)

Inequality (3) and (4) have no common solution, so B is null set or empty set.

B=\{\}

(d)

We need to find the value of |{x ∈ Z | x > 10, x² ≤ 100}| or |B|. It means have to find the number of elements in set B.

|B|=0

|{x ∈ Z | x > 10, x² ≤ 100}| = 0

(e)

We need to find the value of | P(A) |. P(A) is the power set of set A.

Number of elements of a power set is

N=2^n

where, n is the number of elements of set A.

We know that the number of elements of set is 10. So the value of |P(A)| is

|P(A)|=2^{10}

|P(A)|=1024

Therefore |P(A)|=1024.

7 0
3 years ago
Evaluate v(x)=12-2x-5 when x=-2,0, and 5 .<br><br> v(-2)= <br><br> v(0)= <br><br> v(5)=
Vaselesa [24]

Step-by-step explanation:

v(-2)= 12-2x(-2)-5

=12+4-5

=16-5

=11

v(0)= 12-2x0-5

= 12-0-5

=12-5

=7

v(5)= 12-2x5-5

= 12-10-5

=12-5

=7

<em><u>Hope </u></em><em><u>it </u></em><em><u>helps </u></em>

6 0
2 years ago
Last year a state university received 3,560 applications from boys,of those applications,35%were from boys who lived in other st
Aleksandr [31]
\frac{3560}{x} = \frac{40}{100}40x=356000 x= 8900 applications 

you make x the number of total applications   
3 0
3 years ago
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