Answer:
Yes, it is arithmetic with the common difference 2.
Step-by-step explanation:
10-8=2
8-6=2
6-4=2
etc.
The line can be written in the form y=mx+b. Plugging -2 in for m , 1 in for x, and -3 in for y, we get -3=-2*1+b=-2+b. Adding 2 to both sides, we get b=-1 and our equation turns into y=-2x-1 since y and x stay variables. Plugging it into a graphing calculator, we get in (0,b) that b = -1
Answer:
5.48
Step-by-step explanation:
add 2.98 1.75 and 0m75
The coordinates of A will be (2P +M)/3
= (2(16, 14) +(1, 4))/3 = (33/3, 32/3) = (11, 32/3)
The appropriate choice is
(C) (11, 32/3)
_____
You will note that the coordinates of A are the weighted average of the coordinates of the end points. The weighting is the reverse of the ratio of the line segments. That is, the point adjacent to the shortest segment gets the highest weighting. (This is typical of the solution to "mixture" problems.)
Answer:
Step-by-step explanation:
We have the function:
![h(x)=f[f(x)]](https://tex.z-dn.net/?f=h%28x%29%3Df%5Bf%28x%29%5D)
And we want to find:
So, we will differentiate function <em>h</em>. By the chain rule, this yields:
![h^\prime(x)=f^\prime[f(x)]\cdot f^\prime(x)](https://tex.z-dn.net/?f=h%5E%5Cprime%28x%29%3Df%5E%5Cprime%5Bf%28x%29%5D%5Ccdot%20f%5E%5Cprime%28x%29)
Then it follows that:
![h^\prime(1)=f^\prime[f(1)]\cdot f^\prime(1)](https://tex.z-dn.net/?f=h%5E%5Cprime%281%29%3Df%5E%5Cprime%5Bf%281%29%5D%5Ccdot%20f%5E%5Cprime%281%29)
Using the table, we acquire:
And using the table again, we acquire:
Evaluate. Hence:
