Answer:
Interested
Step-by-step explanation:
Here For The Answer As Well
Divide them and youll get your answer
Good job, you got the equations! XD
I'll just help you solve
Multiply the 2nd row by 9
<span>9x+9y=117</span>
<span><span><span>9x+27y=207
</span></span></span>Subtract the 2nd row from the 1st row
<span><span><span>−18y=−90
</span></span></span>Divide both sides by <span>−18</span>
<span><span><span>y=<span><span>−90/</span><span>−18
</span></span></span></span>Two negatives make a positive
<span><span>y=<span><span>90/</span><span>18</span></span></span><span></span></span><span>
y = 5
Substitute 5 into an equation
9x+9(5)=11<span>7
</span>9x+45=11<span>7
</span>Subtract <span>45</span> from both sides
<span><span><span>9x=117−45
</span></span></span>9x=7<span>2
</span>Divide both sides by <span><span>9</span></span>
x = ___
Hope this will help</span></span>
Answer:
1.) 9
2.) 20
Step-by-step explanation:
1.) 39 is incorrect because they didn't follow the PEMDAS rule.
They subtracted 2 from 15 which is 13, and then they multiplied 13 by 3.
<u>The correct way is to multiply 2 times 3 which is 6, and then subtract 6 from 15 which is 9.</u>
<u />
2.) 12 is incorrect because they didn't use PEMDAS.
They added 8 to 16 which is 24, and then divided 24 by 2.
<u>The correct way is to divide 8 by 2 which is 4, and then add for to 16 which 20.</u>
Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209