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pogonyaev
3 years ago
12

What is the GCF of 36 and 68?

Mathematics
2 answers:
NeTakaya3 years ago
4 0

Answer:

The greatest common factor of 36 and 68 is 4

Step-by-step explanation:

36÷4=9

68÷4=17

andreev551 [17]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
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Answer:

y = 360(1.03)x

Step-by-step explanation:

F = P x (1 + i)^n

F is the future worth, P is the present worth, I will be the interest rate, and n is the number of years. F = ($360)(1.03)^x

The principal amount of the money = $360

Annual rate of interest = 3%

Thus, the amount after x years which is increased by 3%.

Since, this amount represented by y,

The required equation that represents the amount of money in Josiah’s  account, y, after x years is, = 360(1+\frac{3}{100} )^x\\ = 360(1+0.03 )^x\\ = 360(1.03 )^x

This amount represented by y,

Therefore, the required equation that represents the amount of money in Josiah’s account, y, after x years is,

y = 360(1.03 )^x

Hope this helps you!

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5 0
3 years ago
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Find the least common multiple of 18, 24, 42
Lana71 [14]

Answer: 504. Multiple for : 18, 24 and 42. Factorize of the above numbers : 18 = 2 • 32 24 = 23 • 3. 42 = 2 • 3 • 7

5 0
3 years ago
Sally has decided to spend some time over two days soving math problems. She figures that on the first day she wil be able to so
erastova [34]

A system of equations for this would be

19x + 11y = 273

and

12x + 17y = 283.

X is the amount of minutes to solve one long division problem and y is the amount of minutes to solve a graphing problem.

How To Solve This System of Equations.

Multiply both by 17 and 11 respectively for them to have the greatest common factor for y. So now both equations are:

323x + 187y= 4641

132x + 187y= 3113.

Subtract both equations and you have left:

191x = 1528.

Divide both sides by 191 and you find x.

X = 8.

Answer

It takes Sally 8 minutes to do one Long Division Problem.


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6 0
3 years ago
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2x-9y=26<br> 6x-2y=-22<br> solve by substitution step by step please
lord [1]

Answer:

y=-8

x=-23

Step-by-step explanation:

see attached document

3 0
2 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

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t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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