A quadratic function whose vertex is the same as the y-intercept has the equation
y=x^2+k (where k is the y-intercept, with vertex (0,k))
Since the vertex coincides with the y-intercept, the axis of symmetry is x=0.
No solution because everything cancels out
Find<span> the </span>Equation<span> of a Line Given That You </span>Know<span> Its </span>Slope<span> and Y-Intercept. The </span>equation<span> of a line is usually written as y=mx+b where m is the </span>slope<span> and b is the y-intercept. If you </span>know<span> the </span>slope<span> (m) any y-intercept (b) of a line, this page will show you </span>how to find<span> the </span>equation<span> of the line. thats the method i use</span>
Answer:
see below:
Step-by-step explanation:
2y–6=0
a. slope intercept form using y = mx + b
y = 6/2
y = 3
b. slope: use the slope intercept form: y = mx + b
slope = m = 0
c. y-intercept = (0,3)
