Determine if the statement is true or false 10,000-99,999<0

A bicycle wheel with diameter 16 inches rides over a screw in the street. The screw is on level ground before it

34kurt

Answer:

16 inches

Step-by-step explanation:

<em>Note: it should say 56π inches instead of 56 inches otherwise no option is correct</em>

<u>Given</u>

Diameter of the wheel = 16 in

<u>Full circumference of the wheel </u>

C =πd = 16π

<u>Bike moves </u>

56π

<u>The wheel turns:</u>

56π /16π = 3.5 times

We only consider her 0.5 of full turn of the wheel to identify the screw position

Since we consider the turns from the ground level as the initial position of the screw, the screw position in the end will be half turn opposite to ground level.

This is the full diameter length, which is 16 inches

So correct answer option is 16 inches

3 0

3 years ago

PLEASE HELP ME SOLVE THIS!<br> GIVING ALL MY POINTS!

maria [59]

It’s the first box goes to the 3rd missing thing and the second goes to the 4th and the 3rd goes to the 1st and 4th goes to the 2nd I think if that makes sense

7 0

3 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

3 years ago

WILL MARK BRAINLIEST IF CORRECT

RideAnS [48]

The answer would be “D” because it’s is 4 less than 7j.

7 0

3 years ago

COULD SOMEONE WRITE FORMAT THEN WRITE EQUIVALENT FRACTION AND MIXED NUMBER 11.09 21.06 0.06 0.50 6.15 AND 7.41

Igoryamba

I think you mean write in word format so yea

11.09
"Eleven and 9 hundredths"
To convert decimals to fractions first put the decimal over 1, multiply by ten for every number after the decimal point and simplify.

(11.09/1)(10)(10) *Because there are 2 numbers after the . 0 and 9*

1109/100
This will be the most simplified you can get it!
As a mixed number:
11 9/100

Follow these steps for the rest!

21.06
"twenty one and six thousandths"
1053/50
21 3/50

0.06
"six thousandths" or
"zero and six thousandths"
3/50

0.50
"fifty thousandths" or "five tenths" since 0.50=0.5
1/2

6.15
"six and fifteen thousandths"
123/20
6 3/20

7.41
"seven and fourty one thousandths"
741/100
7 41/100

I HOPE THIS HELPS

7 0

3 years ago

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